CREATE TABLE EMPLOYEE(EmpID INT PRIMARY KEY , EmpFirstName VARCHAR(100),EmpLastName VARCHAR(100), City VARCHAR(10),ManagerID INT, Salary int ,Designation varchar(10))
1. Adding Constraint between two tables, to update a foreign key relation ship. You need to alter the child table.
ADD CONSTRAINT emp_for FOREIGN KEY (EmpID)
REFERENCES EMPLOYEE(EmpID)
Its because, you need to populate data in the master table and corresponding column should be populated in the child table.
Output:
(1 row(s) affected)
INSERT INTO EMPLOYEE(EmpID, EmpFirstName,EmpLastName,City,Salary) VALUES(1,'Venkat','Prabu','Dharmapuri',1000)
Violation of PRIMARY KEY constraint 'PK__EMPLOYEE__3C69FB99'. Cannot insert duplicate key in object 'dbo.EMPLOYEE'.
Its because we are trying to insert duplicate key into the primary key column.
Let make a try with other insert statements,
INSERT INTO EMPLOYEE(EmpID, EmpFirstName,EmpLastName,City,Salary,Designation) VALUES(3,'Karthi','Prabu','Salem',2000,'Lead')
INSERT INTO EMPLOYEE(EmpID, EmpFirstName,EmpLastName,City,Salary,ManagerID,Designation) VALUES(4,'Lakshmi','Prabu','Chennai',100,3,'Dev')
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INSERT INTO EMPLOYEEDETAILS VALUES(2,'MBA',100)
INSERT INTO EMPLOYEEDETAILS VALUES(3,'BA',10)
INSERT INTO EMPLOYEEDETAILS VALUES(4,'BE',50)
INSERT INTO EMPLOYEEDETAILS VALUES(4,'BE',500)
select * from Employeedetails
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select max(salary),city from Employee Group by city
select max(salary),city from Employee where Salary >=1000
Group by city
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select sum(salary) from Employee
select sum(salary),designation from Employee Group by designation
select count(*) from employee
I need an employee with First name as "Venkat"
select EmpID,EmpFirstName from employee where EmpFirstName='Venkat'
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select EmpID,EmpFirstName from employee where EmpFirstName like 'V%'
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I need an employee with Firstname having second letter as "e"
select EmpID,EmpFirstName from employee where EmpFirstName like '_e%'
I need an employee with firstname ended with the letter "t"
select EmpID,EmpFirstName from employee where EmpFirstName like '%t'
I need an employee whose city is "Chennai"
select EmpID,EmpFirstName from employee where city ='Chennai'
6. List down the employees having more than one extension number
select empid from employeedetails group by empid having count( EmpExtn)>1
2 comments:
cool blog, i like it. one suggetion bro, please change the bg color of th page if you can, i sometimes have to select the whole text to read it
in 6th query do we need group by empid? its unique right? can't we directly use having?
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